Java Collection | Set 3 (HashMap) Part-1 Geeks For Geeks

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 class Solution{

    static int map(int n, String keys[], int arr[], String s)

    {

        HashMap<String,Integer> map1=new HashMap<String,Integer>();

        

        for(int i=0;i<keys.length;i++){

            map1.put(keys[i],arr[i]);

        }

        int val=0;

        if(map1.containsKey(s)){

           val=map1.get(s);

        }

        else{

            val=-1;

        }

        return val;

          

    }

}


Time: O(Length of string array or key array) [GFG Time: 0.2/2.2]

Space: O(n)


Thanks for Reading.😇


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